Well Thought I would release this to the public to test, It has many bugs but does work 
A couple of things you must done before using Autogreeter, Enable “Notify Me When User Joins” option in the beyluxe room(make sure its ticked). when starting the auto greeter make sure to tick the room you want to auto greet, this version supports multiple rooms that are open
Enjoy
Auto Greeter ScreenShot - Test Version
Download:
Well I was looking at my awstats for cheesydoodle today, I found it very interesting that just one little file could cause so much band width…
Stats For Last Months File types
The file is a small 14kb text file … lol but it generates over 5GB of bandwidth per month. Well we can expect atleast double that once the new paltalk 9.9 crack is released. And will be released here Exclusively on Cheesydoodle First, After that it will be released on DutchPlace.nl..
Well I was browsing through some old posts at a forum I have been with for a few years and stumbled across one of my Old vb6 projects “Index Leecher” I downloaded it because I dont have the source code anymore let alone code with vb6, And to my surprise it still works a treat So I thought I would share some of my old school projects with you…this project more than likely contains many bugs and is no longer supported by me, It was just a one off project..
Info:
Index leecher uses google search engine to find servers with folders containing mp3s, oggs, ebooks, rar files, zip files ect ect ect, its very useful because it doesn’t depended on P2P sharing instead it just leeches the results using some “google hacks”
ScreenShot:
Download:
String1 = 1 charactor from username and 1 charactor from HD serial
so if ..
Username = Departure
HD serial = 08DE56F
Then String1 would = D0e8pDaEr5t6uFre
Now we take String1 and add i together 3 times…
String2 = String1 + String1 +String1
String2 = D0e8pDaEr5t6uFreD0e8pDaEr5t6uFreD0e8pDaEr5t6uFre
Okay now we know this string…
in the password kept in the registry of paltalk we have 4 digits for each character of password, for example if my password was “Freak”
then paltalk registry would like this
F r e a k
xxxx xxxx xxxx xxxx xxxx <--- paltalk registry encrypted password.
So thats a 5 byte password, in each 4 digits (xxxx) we drop the last digit, its not used and has something to do with time, Say for example the 5 lots of digits looked like this…
2341 8256 2516 4098 3789
we would drop the last digit of each group of digits like this
234 825 251 409 378
so now we start from the LAST character of our String2 and we create something
like this…
String2 = D0e8pDaEr5t6uFreD0e8pDaEr5t6uFreD0e8pDaEr5t6uFre
paltalk registry encrypted value after droping last digit =
234 825 251 409 378
So…….
1st Password Char = char(234 – ascii code(e) – 0 – 122)
Now we go back to the begining of String2 to continue,Only the First password charactor was using the last of our string2..
2nd Password Char = char(825 – ascii code(D) – 1 – 122)
3rd Password Char = char(251 – ascii code(0) – 2 – 122)
4th Password Char = char(409 – ascii code(e) – 3 – 122)
5th Password Char = char(378 – ascii code(8) – 5 – 122)
So if you know the ascii table you have no problems translating this into a math sum
example from above..
ascii values: e = 101, D = 68, 0 = 48, e = 101, 8 = 56
so the sum would look like this…
1st. 234 – 101 – 0 – 122 = 11
2nd 825 – 68 – 1 – 122 = 634
3rd 251 – 48 – 2 – 122 = 79
4th 409 – 101 – 3 – 122 = 183
5th 378 – 56 – 4 -122 = 196
Then just convert the result for each charactor back to ascii, No point doing it for this eaxmple as I just made these values up randomly and proberly wont convert to a real value in the ascii table…
well I was checking with different nicknames that use the password 123456 and it seems every nick I tested had the same encryption string, Which means paltalk has pre set value for each position of the password, then it just adds the matching charactor of your password
Example:
1.Position 1 of password = 241
2.Position 2 of password = 287
3.Position 3 of password = 302
4.Position 4 of password = 303
5.Position 5 of password = 307
6.Position 6 of password = 324
Now if you have a password “123456″ then
Position Paltalk Your password Result Final
1. 241 + 1 = 242 + RandomNumber
2. 287 + 2 = 289 + RandomNumber
3. 302 + 3 = 305 + RandomNumber
4. 303 + 4 = 307 + RandomNumber
5. 307 + 5 = 312 + RandomNumber
6. 324 + 6 = 330 + RandomNumber
Or lets say you had a password with “476987″
Position Paltalk Your password Result Final
1. 241 + 4 = 245 + RandomNumber
2. 287 + 7 = 294 + RandomNumber
3. 302 + 6 = 308 + RandomNumber
4. 303 + 9 = 312 + RandomNumber
5. 307 + 8 = 315 + RandomNumber
6. 324 + 7 = 331 + RandomNumber
Test it for your self, make a new nick with a password “476987″ and see if you get the same result 
X = Random Number
so the pass should look like this: 245X294X308X312X315X331X
Update:
Paltalk Only allows 12 characters max length for password, so here are the paltalk static numbers for each positions
1.241
2.287
3.302
4.303
5.307
6.324
7.244
8.331
9.307
10.321
11.232
12.289
I got this by using a password “000000000000″ then removing the random number, as you can see it matches in perfect with what I was explaining above
so my paltalk encrypted password = “241928743028303730703240244233193071321423242898″
Now to make a password stealer would be very easy, But because im against that sort of activity I wont be explaining the methods you need to use.
Update 2:
here are the character values if you use ascii in your password
“a..z” = “49..74″ for Example (“a” = 49) (“b” = 50) (“c” = 51) ect….
This is for lower case characters!!
“A..Z” = “17..42″ for Example (“A” = 17) (“B” = 18) (“C” = 19) ect….
This is for Upper case characters!!
Example if I had a password called “cunix1″ the value you need to add to the paltalk static positions would be
1. 51 = c
2. 69 = u
3. 62 = n
4. 57 = i
5. 72 = x
6. 1 = 1
so going by our paltalk magic numbers…
Position Paltalk Your password Result Final
1. 241 + 51 = 292 + RandomNumber
2. 287 + 69 = 356 + RandomNumber
3. 302 + 62 = 364 + RandomNumber
4. 303 + 57 = 360 + RandomNumber
5. 307 + 72 = 379 + RandomNumber
6. 324 + 1 = 325 + RandomNumber
X = Random Number
your encrypted password = 292X356X364X360X379X325X
Infomation:
HipACryp was my first attempt at making a working exe crypter, It hasn’t been update since 2008, But I intended to add compression later down the track and include some more up to date features. It has been tagged by Exe scanners and antivirus engines, So using it for malware is not advised. I dont support malware of any kind and this project was made to obscure the source code to some projects that I have done. This can be unpacked using basic reverse engineer MUP(Manual Un-Packing) methods, so nothing special here
ScreenShot:
HipACryp ScreenShot
Download:
Welcome to CheesyDoodle.com!
This site will be information I have gathered over the years dealing with paltalk messenger system. It wont be limited to paltalk because I would also like to share other information I have on other messenger systems and also a blog dealing with my progress with programming with Delphi, I hope you find something interesting on this site